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You can certainly define generic delegates, after all, that's exactly what func and action are Passing arguments to c# generic new () of templated type asked 16 years, 4 months ago modified 1 year, 9 months ago viewed 272k times They are treated as generic definitions, just like generic interfaces and classes are.
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What keeps us from comparing the values of generic types which are known to be icomparable What is the preferred way to get around it using t.class? Doesn't it somehow defeat the entire purpose of generic constraints?
My question is related to is there a reasonable approach to "default"
Type parameters in c# generics?, but using an inner generic class that approach doesn't work The generic parameter type will be the same for all methods, so i would like it at the class level I know i could make a generic version and then inherit from it for the int version, but i. I have few methods that returns different generic lists
Exists in.net any class static method or whatever to convert any list into a datatable The only thing that i can imagine is use reflecti. Using lookupdictionary = system.collections.generic.dictionary<string, int> Now i want to accomplish the same with a generic type, while preserving it as a generic type
I am trying to combine a bunch of similar methods into a generic method
I have several methods that return the value of a querystring, or null if that querystring does not exist or. I have a generics class, foo<t> In a method of foo, i want to get the class instance of type t, but i just can't call t.class
